x=0.6x^2+4x-35

Solution for x=0.6x^2+4x-35 equation:

x=0.6x^2+4x-35

We move all terms to the left:

x-(0.6x^2+4x-35)=0

We get rid of parentheses

-0.6x^2+x-4x+35=0

We add all the numbers together, and all the variables

-0.6x^2-3x+35=0

a = -0.6; b = -3; c = +35;
Δ = b2-4ac
Δ = -32-4·(-0.6)·35
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{93}}{2*-0.6}=\frac{3-\sqrt{93}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{93}}{2*-0.6}=\frac{3+\sqrt{93}}{-1.2}
$